Phoebe and Her Unicorn by Dana Simpson for December 05, 2018

Don’t be afraid to just let Prunella win. It’s not all bad at the bottom of the popularity chain.

https://ozyandmillie.org/1999/12/01/ozy-and-millie-261/

Regardless of what it sounds like when you try to describe it.

oh, this story is getting more and more interesting

Marigold is popular with at least ONE unicorn – herself!

This is indeed getting interesting. I do believe Dakota compared herself to a goblin. This will be quite the battle.

Is the question relevant? Every individual unicorn thinks of themself as the greatest, surely.

It’s “cooler that she,” not “cooler than her.”

Well, is she or the unicorn who always hides because he outshines the rest.

Found this a while back:

https://www.deviantart.com/avastindy/art/Marigold-and-Phoebe-in-Equestria-450032386

I have a feeling that Dakota is in for a very rough time of it; her ego may very well be severely damaged.

But what if… to be popular as a goblin you have to be unpopular (i.e. unlikable)? So the most popular is really the most disliked? Ah, hell, Dakota still might win.

I love Marigold’s answer to Dakota’s question.

Dakota is approaching ‘terminally cool’, where you are too cool for your own good! On a graph, there is the linear phase, where the harder you try, the cooler you are. Then, at ‘optimally cool’, you start to get diminishing returns. Then you reach ‘maximally cool’ at the top of the graph. Then on the other side of the peak, the harder you try, the less cool you are, until you go off the deep end into ‘terminally cool’, where your coolness is working against you. The graph for working out is about the same, where you can end up ‘over-training’. Similarly, there is ‘having attitude’, ‘having an attitude’, progressing to having an ‘attitude problem’.

Know the difference between prose and dialog. We don’t normally speak in complete sentences either. To do so would be unusual.

ya know