The answer is one. That is assuming that there is only 3 children in the class, the assumption based upon only three children mentioned. However, even if there were the average of twenty children in the class, the answer would still be one. 61 minus 1 equals 60, each of the 3 mentioned children would have 20, if there were 20 children in the class, each child would have 3. You’d round down on Joe’s.
Believe me, I am NO mathematician. However. Dot has 20 gumballs. Jack has 40. Joe has 1/3 or 13 and 1/3. Good so far? Dot gives Jack half, she now has 10 and he has 50. He chews 25, leaving him 25. Right? So, we have amounts of 10, 25 and 13 and 1/3. So the lowest amount is 10, which would mean taking 15 from Jack and 3 and 1/3 from Joe. Or 18 and 1/3 altogether. Am I wrong? OR, does the teacher take away ALL their gumballs and redistribute them? But I still can’t get away from that 1/3 gumball.
You may still go to Harvard, you’ll just have to pay for a ringer to take your admissions exams like these folks did: https://abcnews.go.com/US/hollywood-actors-ceos-charged-nationwide-college-admissions-cheating/story?id=61627873
The real question is how many gumballs will the teacher need to take away from everybody for them all to stop comparing gumballs and get back to working on the lesson?
Macushlalondra about 5 years ago
What a ridiculous question. They’re designed to drive you straight up the wall.
Eric Sobocinski Premium Member about 5 years ago
Joe has 13 1/3 gumballs? How do you get 1/3 of a gumball, and why would you keep it?
The teacher takes away 15 from Jack and 3 1/3 from Joe, so I guess Joe doesn’t need to worry about it anymore, but still….
Back to Big Mike about 5 years ago
I’m thinking it’s 38.33 total taken by the teacher. 35 from Jack and 3.33 from Joe. Now they all have 10.
Nighthawks Premium Member about 5 years ago
what do I have to do to get free gumballs?
Kroykali about 5 years ago
Just put down “All of them”.
serial232 about 5 years ago
The answer is one. That is assuming that there is only 3 children in the class, the assumption based upon only three children mentioned. However, even if there were the average of twenty children in the class, the answer would still be one. 61 minus 1 equals 60, each of the 3 mentioned children would have 20, if there were 20 children in the class, each child would have 3. You’d round down on Joe’s.
Diat60 about 5 years ago
Believe me, I am NO mathematician. However. Dot has 20 gumballs. Jack has 40. Joe has 1/3 or 13 and 1/3. Good so far? Dot gives Jack half, she now has 10 and he has 50. He chews 25, leaving him 25. Right? So, we have amounts of 10, 25 and 13 and 1/3. So the lowest amount is 10, which would mean taking 15 from Jack and 3 and 1/3 from Joe. Or 18 and 1/3 altogether. Am I wrong? OR, does the teacher take away ALL their gumballs and redistribute them? But I still can’t get away from that 1/3 gumball.
Spock about 5 years ago
Come on, Len, that’s a task for a 2nd-grader! How old is Colin?
scyphi26 about 5 years ago
Ugh…math. Yeah, no, you two are on your own now. Peace out!
InquireWithin about 5 years ago
You may still go to Harvard, you’ll just have to pay for a ringer to take your admissions exams like these folks did: https://abcnews.go.com/US/hollywood-actors-ceos-charged-nationwide-college-admissions-cheating/story?id=61627873
Auntie Socialist about 5 years ago
The real question is how many gumballs will the teacher need to take away from everybody for them all to stop comparing gumballs and get back to working on the lesson?
Saucy1121 Premium Member about 5 years ago
Since when is ANY gum allowed in the class? Certainly wasn’t in the dark ages when I was in Elementary School.
oakie817 about 5 years ago
if that was a question on my test back when I was that age, my answer would have been "i don’t chew gum’’
SteveSanders1 about 5 years ago
When I was in school the answer was obvious. The teacher took all the gumballs leaving all the kids equally without any. Taught us all about taxation!