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Calvin and Hobbes by Bill Watterson for April 27, 1987

19 Comments

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    DragonWizzard  about 8 years ago

    This is how I fell when I get these math problems.

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    ilovemypapillon  over 7 years ago

    I don’t think that is possible to solve whether you are dead or alive

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    comicmath  over 7 years ago

    Maybe with a diagram

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    overlived  almost 7 years ago

    two inches less than a foot and i’m in zombie town

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    jeanmichel  almost 7 years ago

    Hardcore math problem for a 6-year-old. It depends on the angle BAC.Here is a graph of the set of the solutions with the value of AC depending on the value of the angle BAC in radians : http://i.imgur.com/PhoSi.pngI’d rather walk dead than having to solve this by hand, searching for limits and tangents.

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    WilliamBill  almost 7 years ago

    Isn’t it a straight line? 10"?

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    bmonk  almost 7 years ago

    If they are in a straight line, it should be 10 inches, or 3 1/3 inches. I believe the possible answers lie on a hyperbola, so the answer may be anything over 3 1/3 inches. A diagram, or more constraints, sure would help.

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    yow4zip Premium Member almost 7 years ago

    That’s why zombies eat brains.

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    pink54836  almost 5 years ago

    um i think this just goes in circles

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    VRAssassinCreed  over 4 years ago

    10

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    BarrelO'Molasses Premium Member over 2 years ago

    10"

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    zahaanr7  over 1 year ago

    10"

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    Comics Man  about 1 year ago

    10"

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    donerito  about 1 year ago

    It’s only 10" if you make assumptions (and we all know that makes an ass-of-u-&-me).

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    MarkFaxas  6 months ago

    AC = 2ABBC = 5BC = ABAB = 5AC = 2AB = 2 × 5 = 10AC = 1010 inches.

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    divad27182  2 months ago

    The lengths of the sides are X, 2X, and 5. We are asked to find 2X. The term “distance” is used, so the triangle inequality applies. Therefore:

    X + 2X >= 5

    X + 5 >= 2X

    5 + 2X >= X

    Reducing, and solving for 2X:

    2X >= 3 1/3

    2X <= 10

    2X >= -10

    So all we know, without further assumptions is that AC is between 3 1/3 and 10, inclusive.

    Note that this analysis does not assume and particular distance function. In particular it does not assume a distance function derived from a euclidian norm. But I doubt Calvin’s teacher could even tell you what that means.

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    Comic Lover 2020 Premium Member 2 months ago

    AB: 5"

    BC: 5"

    AC: 10"

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