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Calvin and Hobbes by Bill Watterson for April 27, 1987

20 Comments

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    DragonWizzard  almost 9 years ago

    This is how I fell when I get these math problems.

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    ilovemypapillon  over 8 years ago

    I don’t think that is possible to solve whether you are dead or alive

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    comicmath  about 8 years ago

    Maybe with a diagram

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    overlived  over 7 years ago

    two inches less than a foot and i’m in zombie town

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    jeanmichel  over 7 years ago

    Hardcore math problem for a 6-year-old. It depends on the angle BAC.Here is a graph of the set of the solutions with the value of AC depending on the value of the angle BAC in radians : http://i.imgur.com/PhoSi.pngI’d rather walk dead than having to solve this by hand, searching for limits and tangents.

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    WilliamBill  over 7 years ago

    Isn’t it a straight line? 10"?

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    bmonk  over 7 years ago

    If they are in a straight line, it should be 10 inches, or 3 1/3 inches. I believe the possible answers lie on a hyperbola, so the answer may be anything over 3 1/3 inches. A diagram, or more constraints, sure would help.

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    yow4zip Premium Member over 7 years ago

    That’s why zombies eat brains.

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    pink54836  over 5 years ago

    um i think this just goes in circles

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    VRAssassinCreed  almost 5 years ago

    10

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    BarrelO'Molasses Premium Member almost 3 years ago

    10"

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    zahaanr7  about 2 years ago

    10"

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    Comics Man  almost 2 years ago

    10"

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    donerito  almost 2 years ago

    It’s only 10" if you make assumptions (and we all know that makes an ass-of-u-&-me).

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    MarkFaxas  about 1 year ago

    AC = 2ABBC = 5BC = ABAB = 5AC = 2AB = 2 × 5 = 10AC = 1010 inches.

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    divad27182  11 months ago

    The lengths of the sides are X, 2X, and 5. We are asked to find 2X. The term “distance” is used, so the triangle inequality applies. Therefore:

    X + 2X >= 5

    X + 5 >= 2X

    5 + 2X >= X

    Reducing, and solving for 2X:

    2X >= 3 1/3

    2X <= 10

    2X >= -10

    So all we know, without further assumptions is that AC is between 3 1/3 and 10, inclusive.

    Note that this analysis does not assume and particular distance function. In particular it does not assume a distance function derived from a euclidian norm. But I doubt Calvin’s teacher could even tell you what that means.

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  18. Flag
    Comic Lover 2020 Premium Member 11 months ago

    AB: 5"

    BC: 5"

    AC: 10"

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